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Section 5.2 The Characteristic Equation

Handout 5.2 The Characteristic Equation

Note 5.14.

Similar matrices are introduced in Section 5.2, but are not used until Section 5.3. We will wait to introduce them in Section 5.3.
Recall:
\(\lambda\) is an eigenvalue of \(A\) if and only if \((A-\lambda I)\) is not invertible.
Therefore, to calculate the eigenvalues of \(A\text{,}\) we can need to find all \(\lambda\) so that
\begin{equation*} \det(A-\lambda I)=0. \end{equation*}

Definition 5.15.

The quantity \(\det(A-\lambda I)\) is the characteristic polynomial of \(A\text{.}\)
The equation \(\det(A - \lambda I) = 0\) is the characteristic equation of \(A\text{.}\)
The roots of the characteristic polynomial are the eigenvalues of \(A\text{.}\)

Example 5.16.

Find the characteristic polynomial of
\begin{equation*} A=\begin{bmatrix} 5 \amp 2\\ 2 \amp 1 \end{bmatrix}. \end{equation*}
Then determine the eigenvalues of \(A\text{.}\)

Example 5.17.

\begin{equation*} M=\begin{bmatrix} a \amp b\\ c \amp d \end{bmatrix}. \end{equation*}
Express the characteristic equation of \(M\) in terms of \(\det(M)\text{.}\) What is the equation when \(M\) is singular?

Definition 5.19. Algebraic Multiplicity.

The algebraic multiplicity of an eigenvalue is its multiplicity as a root of the characteristic polynomial.

Example 5.20.

Compute the algebraic multiplicities of the eigenvalues for
\begin{equation*} A = \begin{bmatrix} 1 \amp 0 \amp 0 \amp 0\\ 0 \amp 2 \amp 0 \amp 0\\ 0 \amp 0 \amp -1 \amp 1\\ 0 \amp 0 \amp 0 \amp -1 \end{bmatrix}. \end{equation*}

Definition 5.21. Geometric Multiplicity.

The geometric multiplicity of an eigenvalue \(\lambda\) is the dimension of \(\operatorname{Nul}(A-\lambda I)\text{.}\)
  1. The geometric multiplicity of an eigenvalue \(\lambda\) is always between 1 and the algebraic multiplicity of \(\lambda\text{.}\) It can never be 0 nor be greater than the algebraic mutliplicy.
  2. Basic example:
    \begin{equation*} \begin{bmatrix} 1 \amp 1\\ 0 \amp 1 \end{bmatrix} \end{equation*}
    has only eigenvalue \(\lambda=1\text{.}\) Its algebraic multiplicity is 2, but its geometric multiplicity is 1.

Example 5.22.

Compute the geometric multiplicities of the eigenvalues for
\begin{equation*} A = \begin{bmatrix} 1 \amp 0 \amp 0 \amp 0\\ 0 \amp 2 \amp 0 \amp 0\\ 0 \amp 0 \amp -1 \amp 1\\ 0 \amp 0 \amp 0 \amp -1 \end{bmatrix}. \end{equation*}

Example 5.23.

For each part below, give an example of a \(5\times 5\) matrix withe the stated properties, if possible.
(a)
The only eigenvalue is \(\lambda=0\text{,}\) but the geometric multiplicity of \(\lambda=0\) is one.
(b)
The only eigenvalues are \(\lambda_1=0\) and \(\lambda_2 = 1\text{.}\) The algebraic multiplicity of \(\lambda_1=0\) is three and the geometric multiplicity of \(\lambda_2 = 1\) is three.
(c)
Exactly three eigenvalues, all with geometric multiplicity equal to 1.

Example 5.24.

Consider the Markov Chain given by
\begin{equation*} \vec x_0= \begin{bmatrix} 1\\ 0 \end{bmatrix}, \quad \vec x_{k+1}=P\vec x_k = \begin{bmatrix} 0.6 \amp 0.4\\ 0.4 \amp 0.6 \end{bmatrix} \vec x_k. \end{equation*}
Two-state Markov chain with symmetric transition probabilities.
Nodes A and B with transitions 0.6 for staying and 0.4 for switching; matrix \(P=\begin{bmatrix}0.6 \amp 0.4\\ 0.4 \amp 0.6\end{bmatrix}\text{.}\)
In the parts below, we will use eigenvalues to describe the long-term behavior of the system.
(a)
Find the eigenvalues of \(P\) and corresponding eigenvectors.
(b)
Use the eigenvalues and eigenvectors to determine what \(\vec x_k\) tends to as \(k\to\infty\text{.}\)

Example 5.25.

True or False: A row replacement operation on a matrix does not change its eigenvalues.

Example 5.26.

For what values of \(k\) does the matrix have one real eigenvalue with algebraic multiplicity 2?
\begin{equation*} A = \begin{bmatrix} -3 \amp k\\ 2 \amp -6 \end{bmatrix} \end{equation*}